Python制作Windows系统服务

最近有个Python程序需要安装并作为Windows系统服务来运行，过程中碰到一些坑，整理了一下。

Python服务类

首先Python程序需要调用一些Windows系统API才能作为系统服务，具体内容如下：

#!/usr/bin/env python
# -*- coding: utf-8 -*-
import sys
import time

import win32api
import win32event
import win32service
import win32serviceutil
import servicemanager


class MyService(win32serviceutil.ServiceFramework):

  _svc_name_ = "MyService"
  _svc_display_name_ = "My Service"
  _svc_description_ = "My Service"

  def __init__(self, args):
    self.log('init')
    win32serviceutil.ServiceFramework.__init__(self, args)
    self.stop_event = win32event.CreateEvent(None, 0, 0, None)

  def SvcDoRun(self):
    self.ReportServiceStatus(win32service.SERVICE_START_PENDING)
    try:
      self.ReportServiceStatus(win32service.SERVICE_RUNNING)
      self.log('start')
      self.start()
      self.log('wait')
      win32event.WaitForSingleObject(self.stop_event, win32event.INFINITE)
      self.log('done')
    except BaseException as e:
      self.log('Exception : %s' % e)
      self.SvcStop()

  def SvcStop(self):
    self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
    self.log('stopping')
    self.stop()
    self.log('stopped')
    win32event.SetEvent(self.stop_event)
    self.ReportServiceStatus(win32service.SERVICE_STOPPED)

  def start(self):
    time.sleep(10000)

  def stop(self):
    pass

  def log(self, msg):
    servicemanager.LogInfoMsg(str(msg))

  def sleep(self, minute):
    win32api.Sleep((minute*1000), True)

if __name__ == "__main__":
  if len(sys.argv) == 1:
    servicemanager.Initialize()
    servicemanager.PrepareToHostSingle(MyService)
    servicemanager.StartServiceCtrlDispatcher()
  else:
    win32serviceutil.HandleCommandLine(MyService)

pyinstaller打包

pyinstaller -F MyService.py

测试

# 安装服务
dist\MyService.exe install

# 启动服务
sc start MyService

# 停止服务
sc stop MyService

# 删除服务
sc delete MyService

本文Python制作Windows系统服务到此结束。困难只能吓倒懦夫懒汉，而胜利永远属于敢于攀登科学高峰的人。小编再次感谢大家对我们的支持！