设z=a+bi则(1+i)z=(1+i)(a+bi)=a-b+(b+a)i=1+√3i得 a-b=1a+b=√3所以a=(√3+1)/2b=(√3-1)/2|z|=√(a²+b²) =√[(4+2√3)/4+(4-2√3)/4] =√2