C语言打印unsigned int，和unsigned long int最大值输出=-1，请问哪里弄错了呢？

代码：#include <stdio.h>#include <limits.h>int main(void){ signed char signed_c; unsigned char unsigned_c; signed short int signed_short_i; unsigned short int unsigned_short_i; signed int signed_i; unsigned int unsigned_i; signed long int signed_long_i; unsigned long int unsigned_long_i; printf("Sizeof(char) = %ld\n", sizeof(char)); signed_c = 0x7F; // 01111 1111 printf("signed char max = %d\t", signed_c); signed_c = 0x80; // (128)1000 0000 反码0111 1111 补码1000 0000 printf("signed char min = %d\n", signed_c); unsigned_c = 0xFF; // 11111 1111 printf("unsigned char max = %d\t", unsigned_c); unsigned_c = 0x00; printf("unsigned char min = %d\n\n", unsigned_c); printf("Sizeof(short int) = %ld\n", sizeof(short int)); signed_short_i = 0x7FFF; // 01111 1111 1111 1111 printf("signed short int max = %d\t", signed_short_i); signed_short_i = 0x8000; // 1000 0000 0000 0000 反码0111 1111 1111 1111补码1000 0000 0000 0000 printf("signed short int min = %d\n", signed_short_i); unsigned_short_i = 0xFFFF; // 11111 1111 printf("unsigned short int max = %d\t", unsigned_short_i); unsigned_short_i = 0x0000; printf("unsigned short int min = %d\n\n", unsigned_short_i); printf("Sizeof(int) = %ld\n", sizeof(int)); signed_i = 0x7FFFFFFF; printf("signed int max = %d\t", signed_i); signed_i = 0x80000000; printf("signed int min = %d\n", signed_i); unsigned_i = 0xFFFFFFFF; printf("unsigned int max = %d, UINT_MAX = %d\t", unsigned_i, UINT_MAX); unsigned_i = 0x00000000; printf("unsigned int min = %d\n\n", unsigned_i); printf("Sizeof(long) = %ld\n", sizeof(long)); signed_long_i = 0x7FFFFFFFFFFFFFFF; printf("signed long int max = %ld\t", signed_long_i); signed_long_i = 0x8000000000000000; printf("signed long int min = %ld\n", signed_long_i); unsigned_long_i = 0xFFFFFFFFFFFFFFFF; printf("unsigned long int max = %ld, ULONG_MAX = %ld\t", unsigned_long_i, ULONG_MAX); unsigned_long_i = 0x0000000000000000; printf("unsigned long int min = %ld\n\n", unsigned_long_i); return 0;}打印输出如图：

额，我百度了下，基本上是找到原因了，d%代表的是int类型，当你传入char,或unsigned char或short或unsigned short，会主动转换为int类型，而无符号的0xff转换为int为0x000000ff,而有符号0xff转换为int为0xffffffff，所以使用d来打印你说的这两个是没有问题的，

C语言打印unsigned int，和unsigned long int最大值输出=-1，请问哪里弄错了呢？

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