Python实现通讯录功能

说实话，第一次写这么长的Python代码，期间遇到了很多问题，但是，最终还是完成了，花了我一天半的时间。

该程序实现了用户的增，删，改，查，主要用到sqlite3模块。对于该模块的知识点，请查看我的另一篇文章SQLite-Python

如有更好的建议，请私信，本人将不胜荣幸，让我们一起来学习Python！

#-*- coding:utf-8 -*-
import sqlite3
#打开本地数据库用于存储用户信息
conn = sqlite3.connect('mysql_person.db')

#在该数据库下创建表，创建表的这段代码在第一次执行后需要注释掉，否则再次执行程序会一直提示：该表已存在
conn.execute('''CREATE TABLE MT
  (ID INT PRIMARY KEY  NOT NULL,
  NAME   TEXT NOT NULL,
  AGE   INT  NOT NULL,
  ADDRESS  CHAR(50),
  SALARY   REAL);''')
print "Table created successfully";
conn.close()

#增加用户信息
def insert():
 ID = input('请输入用户ID:\n')
 NAME = raw_input('请输入用户昵称:\n')
 AGE = input('请输入年龄:\n')
 ADDRESS = raw_input('请输入用户地址:\n')
 SALARY = input('请输入用户薪水:\n')
 sql1 = 'insert into MT(ID,NAME,AGE,ADDRESS,SALARY)'
 sql1 += 'values("%d","%s","%d","%s","%d");'%(ID,NAME,AGE,ADDRESS,SALARY)
 conn.execute(sql1)
 conn.commit()
 print "Records insert successfully"

#删除用户信息
def delete():
 name = raw_input("请输入所要删除的联系人姓名:")
 cursor = conn.execute("SELECT name from MT where name = '%s';"%name)
 for row in cursor:
  if name == row[0]:
   conn.execute("DELETE from MT where name = '%s';"%name)
   conn.commit()
   print "Records delete successfully"
   break
 else:
  print "sorry,不存在该用户"

#修改用户信息
def modify():
 name = raw_input("请输入要修改用户的姓名:")
 print search()
 sql4 = "SELECT id, name, age,address, salary from MT where name = '%s';"%name
 cursor = conn.execute(sql4)
 x = raw_input("请输入要修改用户的新地址:")
 y = input("请输入要修改用户的新年龄:")
 z = input("请输入要修改用户的新薪水:")
 sql3 = "UPDATE MT set address = '%s',age = '%d',\
  salary = '%d' where name = '%s';"%(x,y,z,name)
 conn.execute(sql3)
 conn.commit()
 print "修改成功"
 sql5 = "SELECT id, name, age,address, salary from MT where name = '%s';"%name
 cursor = conn.execute(sql5)
 for row in cursor:
  print "ID = ", row[0]
  print "NAME = ", row[1]
  print "AGE = ",row[2]
  print "ADDRESS = ", row[3]
  print "SALARY = ", row[4], "\n"


#查询用户信息
conn = sqlite3.connect('mysql_person.db')

def search():
 conn = sqlite3.connect('mysql_person.db')
 name = raw_input('请输入要查询的用户姓名')
 sql2 = "SELECT id,name,age, address, salary from MT where name= '%s';" % (name)
 cursor = conn.execute(sql2)
 for row in cursor:
  print "ID = ", row[0]
  print "NAME = ", row[1]
  print "AGE = ",row[2]
  print "ADDRESS = ", row[3]
  print "SALARY = ", row[4], "\n"
  break
 else:
  print "sorry,没有该用户信息"

#显示所有用户信息
def showall():
 cursor = conn.execute("SELECT id, age, name, address, salary from MT")
 for row in cursor:
  print "ID = ", row[0]
  print "NAME = ", row[1]
  print "AGE = ",row[2]
  print "ADDRESS = ", row[3]
  print "SALARY = ", row[4], "\n"
 print "Operation done successfully";
 cursor = conn.execute("select count(*) from MT;")
 for row in cursor:
  print "一共有%d个用户"%row[0]

def menu():
 print '1.新增联系人'
 print '2.删除联系人'
 print '3.修改联系人'
 print '4.查询联系人'
 print '5.显示所有联系人'
 print '6.退出程序'
 print 'What do you want to do?'
while True:
 menu()
 x = raw_input('请输入您的选择菜单号:')
 if x == '1':
  insert()
  continue
 if x == '2':
  delete()
  continue
 if x == '3':
  modify()
  continue
 if x == '4':
  search()
  continue
 if x == '5':
  showall()
  continue
 if x == '6':
  print "谢谢使用！"
  exit()
  continue
 else:
  print "输入的选项不存在，请重新输入！"
  continue

本文Python实现通讯录功能到此结束。荆棘的存在是为了野草不轻易地任人践踏。小编再次感谢大家对我们的支持！