python实现简易通讯录修改版

描述：

上一篇博客我写了一个简单的通讯录，但是还是觉得不够完美：

需要输入ID，虽然ID是主键，但是没有实现自增功能；

忘记加电话号码了；

如果插入用户名相同，则后续的查、改、删功能受到影响；

所以，我这个修改版主要修正了以上三点缺陷。具体如下

将用户ID设置为自增字段，即就是不用输入ID，程序会自动帮你将插入的用户进行排序并附上ID，默认从1开始；SQLite实现主键自增功能，请查看SQLiteAUTOINCREMENT/自动递增这篇博客。
创建表时增加了电话号码字段；
插入的用户名不能重复；
好了，废话不多说，附上新代码，哈哈~~~

#-*- coding:utf-8 -*-

import sqlite3
#打开本地数据库用于存储用户信息
conn = sqlite3.connect('mysql_person.db')

#在该数据库下创建表,创建表的这段代码在第一次执行后需要注释掉，否则再次执行程序会一直提示：该表已存在
conn.execute ('''CREATE TABLE MT_table1(
  ID INTEGER PRIMARY KEY  AUTOINCREMENT,
  NAME      TEXT   NOT NULL,
  AGE      INT    NOT NULL,
  ADDRESS    CHAR(50),
  SALARY     REAL,
  PhoneNumber  INT    NOT NULL);''')
print "Table created successfully";

#增加用户信息
def insert():
  USER_NAME = raw_input('请输入用户昵称:')
  cursor = conn.execute("SELECT name from MT_table1 where name = '%s';"%USER_NAME)
  for row in cursor:
    if USER_NAME == row[0]:
      print "sorry,改用户名已存在，请重新输入用户名"
      break
  else:
    AGE = input('请输入年龄:')
    ADDRESS = raw_input('请输入用户地址:')
    SALARY = input('请输入用户薪水:')
    PhoneNumber = input("请输入联系方式:")
    #为避免代码太长，以下我用字符串的连接特性将代码缩短
    sql1 = 'INSERT INTO MT_table1(NAME,AGE,ADDRESS,SALARY,PhoneNumber)'
    sql1 += 'VALUES("%s","%d","%s","%d","%d");'%(USER_NAME,AGE,ADDRESS,SALARY,PhoneNumber)
    conn.execute(sql1)
    conn.commit()
    print "Records insert successfully"

#删除用户信息
def delete():
  delete_name = raw_input("请输入所要删除的联系人姓名:")
  cursor = conn.execute("SELECT name from MT_table1 where name = '%s';"%delete_name)
  for row in cursor:
    if delete_name == row[0]:
      conn.execute("DELETE from MT_table1 where name = '%s';"%delete_name)
      conn.commit()
      print "Records delete successfully"
      break
  else:
    print "sorry,不存在该用户"

#修改用户信息
def modify():
  update_name = raw_input("请输入要修改用户的姓名:")
  sql6 = "SELECT name from MT_table1 where name = '%s';"%update_name
  cursor = conn.execute(sql6)
  for row in cursor:
    if update_name == row[0]:
      New_addr = raw_input("请输入要修改用户的新地址:")
      New_age = input("请输入要修改用户的新年龄:")
      New_salary = input("请输入要修改用户的新薪水:")
      New_num = input("输入要修改用户的新号码:")
      sql3 = "UPDATE MT_table1 set address = '%s',age = '%d',salary = '%d',PhoneNumber = '%d' where \
      name = '%s';"%(New_addr,New_age,New_salary,New_num,update_name)
      conn.execute(sql3)
      conn.commit()
      print "修改成功"
      sql5 = "SELECT id, name, age,address, salary ,PhoneNumber from MT_table1 where name = '%s';"%update_name
      cursor = conn.execute(sql5)
      for row in cursor:
        print "ID = ", row[0]
        print "NAME = ", row[1]
        print "AGE = ",row[2]
        print "ADDRESS = ", row[3]
        print "SALARY = ", row[4]
        print "PhoneNumber = ",row[5], "\n"
        break
  else:
    print "sorry,不存在该用户信息"


#查询用户信息
def search():
  conn = sqlite3.connect('mysql_person.db')
  search_name = raw_input('请输入要查询的用户姓名')
  sql2 = "SELECT id,name,age, address, salary ,PhoneNumber from MT_table1 where name= '%s';" % (search_name)
  cursor = conn.execute(sql2)
  for row in cursor:
    print "ID = ", row[0]
    print "NAME = ", row[1]
    print "AGE = ",row[2]
    print "ADDRESS = ", row[3]
    print "SALARY = ", row[4]
    print "PhoneNumber = ",row[5], "\n"
    break
  else:
    print "sorry,没有该用户信息"


#显示所有用户信息
def showall():
  cursor = conn.execute("SELECT id, name,age, address, salary ,PhoneNumber from MT_table1")
  for row in cursor:
    print "ID = ", row[0]
    print "NAME = ", row[1]
    print "AGE = ",row[2]
    print "ADDRESS = ", row[3]
    print "SALARY = ", row[4]
    print "PhoneNumber = ",row[5], "\n"
  print "Operation done successfully";
  cursor = conn.execute("select count(*) from MT_table1;")
  for row in cursor:
    print "一共有%d个用户"%row[0]

def menu():
  print '1.新增联系人'
  print '2.删除联系人'
  print '3.修改联系人'
  print '4.查询联系人'
  print '5.显示所有联系人'
  print '6.退出程序'
  print 'What do you want to do?'
while True:
  menu()
  x = raw_input('请输入您的选择菜单号:')
  if x == '1':
    insert()
    continue
  if x == '2':
    delete()
    continue
  if x == '3':
    modify()
    continue
  if x == '4':
    search()
    continue
  if x == '5':
    showall()
    continue
  if x == '6':
    print "谢谢使用！"
    exit()
    continue
  else:
    print "输入的选项不存在，请重新输入！"
    continue

到此这篇关于python实现简易通讯录修改版就介绍到这了。人生，没有永远的伤痛，再深的痛，在切之时，伤口总会痊愈。人生，没有过不去的坎，你不可以坐在坎边等它消失，你只能想办法穿过它。人生，没有永远的爱情，没有结局的感情，总要结束；不能拥有的人，总会忘记。更多相关python实现简易通讯录修改版内容请查看相关栏目，小编编辑不易，再次感谢大家的支持！