生活的激流已经涌现到万丈峭壁，只要再前进一步，就会变成壮丽的瀑布。没有播种，何来收获；没有辛苦，何来成功；没有磨难，何来荣耀；没有黯淡，何来辉煌。
本文实例为大家分享了python实现人民币转大写人民币的具体代码，供大家参考，具体内容如下
直接上代码：
# -*- coding: utf-8 -*-
def changenum( change_number ):
format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"]
format_name = ["分", "角", "元",
"拾","百","千","万",
"拾","百","千","亿",
"拾","百","千","万",
"拾","百","千","兆"]
if type( change_number ) == str:
if '.' in change_number:
try: change_number = float( change_number )
except: raise ValueError, '%s can\'t change'%change_number
else:
try: change_number = int( change_number )
except: raise ValueError, '%s can't change'%change_number
if type( change_number ) == float:
real_numbers = []
for i in range( len( format_name ) - 3, -3, -1 ):
if change_number >= 10 ** i or i < 1:
real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) )
elif isinstance( change_number, (int, long) ):
real_numbers = [ int( i ) for i in str( change_number ) + '00' ]
else:
raise ValueError, '%s can\'t change'%change_number
zflag = 0
start = len(real_numbers) - 3
change_words = []
for i in range(start, -3, -1):
if 0 <> real_numbers[start-i] or len(change_words) == 0:
if zflag:
change_words.append(format_num[0])
zflag = 0
change_words.append( format_num[ real_numbers[ start - i ] ] )
change_words.append(format_name [i+2])
elif 0 == i or (0 == i%4 and zflag < 3):
change_words.append(format_name [i+2])
zflag = 0
else:
zflag += 1
if change_words[-1] not in (format_name[0], format_name[1]):
change_words.append("整")
return ''.join(change_words)
#测试
# print changenum(865324.98)
#查看输出的结果是否正确
到此这篇关于python2.x实现人民币转大写人民币就介绍到这了。在我的生命中，从未遭受过失败，我所遇到的，都是暂时的挫折罢了。更多相关python2.x实现人民币转大写人民币内容请查看相关栏目，小编编辑不易，再次感谢大家的支持！