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#coding:utf-8 #批量修改文件名 import os import re import datetime re_st = r'(\d+)\+\s?\((\d+)\)' #用于匹配旧的文件名,需含分组 re_match_old_file_name = re.compile(re_st) #要修改的目录 WORKING_PATH = r'F:\Gallery' #---------------------------------------------------------------------- def rename_fomat(name): """ 文件重命名格式组织模块(一般修改这里就可以了) NOTE:返回类型必须是unicode """ if name: re_rn = re_match_old_file_name.findall(name) if re_rn and re_rn != []: re_rn = re_rn[0] num = int(re_rn) new_nm = u'NO.%04d' % ( num) return new_nm #---------------------------------------------------------------------- def logs(error): """ 错误记录 """ log = '' LOG_FILE = open(r'./log.txt', 'a') live_info =""" ========== Time : %s title : %s Path : %s ========== """ % ( datetime.datetime.now(), str(error['title']), str(error['index']), ) log += live_info errors = error['error_paths'] for item in errors: item = '%s\n' % item log += item log = log.encode('utf-8') try: LOG_FILE.write(log) except IOError: print u'写入日志失败' finally: LOG_FILE.close() #---------------------------------------------------------------------- def rename(old, new): """ 文件重命名模块 return: 0:rename success 1:the new path is exists -1:rename failed """ if not os.path.exists(new): try: os.renames(old, new) return 0 except IOError: print 'path error:', new return -1 else: return 1 #---------------------------------------------------------------------- def get_dirs(path): """ 获取目录列表 """ if os.path.exists(path): return os.listdir(path) else: return -1 #---------------------------------------------------------------------- def get_input_result(word, choice): """ 获取正确的输入结果 """ correct_result = set(choice) word = '===%s?\n[in]:' % (word) while True: in_choice = raw_input(word) if in_choice in correct_result: return in_choice #---------------------------------------------------------------------- def batch_rename(index, dirs = []): """ 批量修改文件 """ index = unicode(index) errors = [] if dirs == []: dirs = get_dirs(path = index) if dirs and dirs != []: for item in dirs: item = unicode(item) new_name = rename_fomat(item) if new_name : old_pt = u'%s\\%s'% (index, item) new_pt = u'%s\\%s'% (index, new_name) res_rn = rename(old_pt, new_pt) if res_rn != 0: errors.append(item) else: errors.append(item) if errors and errors != []: print 'Rename Failed:' logs({ 'index': index, 'title': 'Rename Failed' , 'error_paths': errors, }) for i, item in enumerate(errors): print item, '|', if i % 5 == 4: print '' print '' else: return -1 #---------------------------------------------------------------------- def batch_rename_test(index): """ 测试 返回过滤结果 """ index = unicode(index) errors = [] correct = [] dirs = get_dirs(path = index) if dirs and dirs != []: for x, item in enumerate(dirs): item = unicode(item) new_name = rename_fomat(item) if new_name : correct.append(item) old_pt = u'%s\\%s'% (index, item) new_pt = u'%s\\%s'% (index, new_name) print '[%d]O: %s' % ( x + 1, old_pt) print '[%d]N: %s' % ( x + 1, new_pt) else: errors.append(item) if errors and errors != []: print 'Not Match:' logs({ 'index': index, 'title': 'Not Match', 'error_paths': errors, }) for i, item in enumerate(errors): print item, '|', if i % 5 == 4: print '' print '' return correct #---------------------------------------------------------------------- def manage(index): """ 程序组织块 """ file_filter = batch_rename_test(index) do_choice = get_input_result( word = 'Do with this(y / n)', choice = ['y', 'n'] ) if do_choice == 'y': batch_rename(index, dirs= file_filter) print 'Finished !' if __name__ == '__main__': path = WORKING_PATH manage(index = path)
到此这篇关于python批量修改文件名的实现代码就介绍到这了。爱情是什么?爱情是两个人在解决了温饱问题之后闲着没事干的时候才需要的东西。更多相关python批量修改文件名的实现代码内容请查看相关栏目,小编编辑不易,再次感谢大家的支持!