AngularJS实现ajax请求的方法

让人生与事业结伴,让生命与使命同行。你要按你所想的去生活,否则,你迟早会按你所生活的去想。

本文实例讲述了AngularJS实现ajax请求的方法。分享给大家供大家参考,具体如下:

【HTML 代码】

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width,user-scalable=no, initial-scale=1">
  <link rel="stylesheet" type="text/css" rel="nofollow noopener noreferrer" href="" />
  <title>angularjs实现 ajax</title>
</head>
<body ng-app="HelloAjax">
  <div ng-controller="HelloAjax">
    <form>
      <input type="text" ng-model="username" />
      <input type="text" ng-model="email" />
    </form>
    <table>
     <tr ng-repeat="user in users">
       <td>{{user.username}}</td>
       <td>{{user.email}}</td>
     </tr>
    </table>
    <button ng-click="get_more();">get more</button>
  </div>
</body>
<script type="text/javascript" src="./js/angular.min.js" charset="utf-8"></script>
  <script type="text/javascript" src="ajax.js" charset="utf-8"></script>
</html>

【js代码 ajax.js】

var myModule = angular.module("HelloAjax",[]);
myModule.controller("HelloAjax",["$scope","$http",function HelloAjax($scope,$http){
  /*
  $scope.users=[{'username':"zhangsan","email":"zs@11.com"},
    {'username':"zhangsan2","email":"zs@22.com"},
    {'username':"zhangsan3","email":"zs@33.com"}];
  */
  $scope.get_more = function(){
    $http({
        method: "POST",
        url: "./ajax.php",
        data:{'username':$scope.username,
           'email':$scope.email
          }
      }).
      success(function(data, status) {
       //$scope.status = status;
        $scope.users = data;
      }).
      error(function(data, status) {
       //$scope.data = data || "Request failed";
       //$scope.status = status;
     });
   }
}]);

【PHP代码 ajax.php】

<?php
//获取参数
$data = file_get_contents("php://input");
$user = json_decode($data);
//查询数据库
$conn = mysql_connect("localhost","root","");
mysql_select_db("test");
$sql ="select username,email from users ";
$res = mysql_query($sql,$conn);
$users = array();
while($row = mysql_fetch_assoc($res)){
  $users[] = $row;
}
//当然这里简化了插入数据库
$users[] = array('username'=>$user->username,
         'email'=>$user->email);
//返回数据库
echo json_encode($users);

希望本文所述对大家AngularJS程序设计有所帮助。

本文AngularJS实现ajax请求的方法到此结束。寂寞的人总是会用心的记住他生命中出现过的每一个人,于是我总是意犹未尽地想起你在每个星光陨落的晚上一遍一遍数我的寂寞。小编再次感谢大家对我们的支持!

您可能有感兴趣的文章
AngularJS tab栏实现和mvc小案例实例详解

基于AngularJS拖拽插件ngDraggable.js实现拖拽排序功能

AngularJS实现的自定义过滤器简单示例

ionic使用angularjs表单验证(模板验证)

用WebStorm进行Angularjs 2开发(环境篇:Windows 10,Angular-cli方式)