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文本仪一个实例讲述了struts2+jquery实现ajax登陆的实现方法，具体步骤如下：
一、新建一个web项目，取名test。配置好struts2的环境,并导入Jquery的js文件到该项目。
二、在com.action包下，新建一个loginAction.java
loginAction.java的代码如下
package com.action;
import org.apache.struts2.convention.annotation.Action;
import org.apache.struts2.convention.annotation.ParentPackage;
import org.apache.struts2.convention.annotation.Result;
import org.apache.struts2.convention.annotation.Results;
import com.opensymphony.xwork2.ActionSupport;
@Action("login")
@ParentPackage(value = "json-default")
@Results({ @Result(name = "success", type = "json", params = { "data", "flag" }), })
public class LoginAction extends ActionSupport {
/**
*
*/
private static final long serialVersionUID = 1751244794407005783L;
private String flag;
private String username;
private String password;
public String execute() {
try {
if (getUsername() == null || getUsername().trim().equals("")) {
setFlag("用户名不能为空");
return SUCCESS;
} else if (getPassword() == null || getPassword().trim().equals("")) {
setFlag("密码不能为空");
return SUCCESS;
} else if (getUsername().trim().equals("admin")
&& getPassword().equals("admin")) {
setFlag("登陆成功");
return SUCCESS;
} else {
setFlag("用户名或密码错误");
return SUCCESS;
}
} catch (Exception e) {
e.printStackTrace();
setFlag("登陆异常");
return SUCCESS;
}
}
public String getFlag() {
return flag;
}
public void setFlag(String flag) {
this.flag = flag;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
}
三、在WebRoot目录下新建index.jsp和success.jsp
index.jsp为登陆界面，success.jsp为登陆成功后跳转的界面。
index.jsp内容如下：
<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme() + "://"
+ request.getServerName() + ":" + request.getServerPort()
+ path + "/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base rel="nofollow noopener noreferrer" href="<%=basePath%>" rel="external nofollow" >
<title>My JSP 'index.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<script type="text/javascript" src="./resource/js/jquery.min.js"></script>
</head>
<script type="text/javascript">
$(document).ready(function() {
$(".loginButton").click(function() {
var name = $("#username").val();//获取登陆用户名
var password = $("#password").val(); //获取登陆密码
$.post("login", {
username : name,
password : password
}, callback, "json");
});
function callback(data) {
var value=data.flag;
if(value=="登陆成功"){
location.rel="nofollow noopener noreferrer" href="./success.jsp" rel="external nofollow" ;
}else{
alert(value);
}
});
</script>
<body>
<input name="username" id="username" type="text" />
<input name="password" id="password" type="password" />
<button class="loginButton" class="btn btn-inverse">登陆</button>
</body>
</html>
本文struts2+jquery如何实现javascript ajax登陆实例详解到此结束。如果你期望成功，以恒心为良友，以经验为参谋，以细心为兄弟，以期望为哨兵。小编再次感谢大家对我们的支持！